a+b = b+a
a*b = b*a
(a+b)+c = a+(b+c)
(a*b)*c = a*(b*c)
a*(b+c)=a*b + a*c
Factorial:
n! = n*(n-1)*(n-2)*...*1
alternative: n! = 1*2*3*...*n
example: 4! = 4*3*2*1 = 24
(am) (an) = am+n
(ab)m = ambm
(am)n = amn
a0 = 1
(am)/(an) = am-n
a-m = 1/(am)
Note:
(-1) n = 1 is true if
n is an even integer ( n modulo 2 = 0)
(-1) n = -1 is true if
n is an odd integer ( n modulo 2 ≠ 0)
An equation that has the form: ax2+bx+c = 0 can be solved via this formula:
(a + b)1 = a + b
(a + b)2 = a2 + 2ab + b2
(a + b)3 = a3 + 3a2b + 3ab2 + b3
a2 - b2 = (a - b) (a + b)
a3 - b3 = (a - b)(a2 + ab + b2)
0/x = 0 where x is not equal to 0.
a0 = 1 & 00 = 1
0a = 0 where a is not equal to zero
a*0 = 0
a/0 is undefined (don't do it, you will open a black hole!)